I am hoping for some insight for modeling the efficiencies of split system heat pumps and other such stand alone systems.

In this case, the shop drawing provides the ARI rated efficiencies which include the fan power. But this shop drawing does not provide the fan motor power.

In the past I would convert the rated EER to COP using COP = EER/3.4121 and I would assume no fan power as the rating includes the fan power. But this project is being submitted to the USGBC and I am worried that the GBCI may have an issue with this.

As Maria pointed out, 90.1-2013 now provides the formula to convert EER to COP, removing the fan power. The baseline fan power would be calculated using the formulas in G3.1.2.10. Would it be best to use the same method to calculate the proposed case fan power and COP?

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Christopher Jones, P.Eng.
Senior Engineer

WSP Canada Inc.
2300 Yonge Street, Suite 2300
Toronto, ON M4P 1E4
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www.wspgroup.com